x(x-3)=x^2+8-4x

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Solution for x(x-3)=x^2+8-4x equation: 



x(x-3)=x^2+8-4x

We move all terms to the left:

x(x-3)-(x^2+8-4x)=0

We multiply parentheses

x^2-3x-(x^2+8-4x)=0

We get rid of parentheses

x^2-x^2-3x+4x-8=0

We add all the numbers together, and all the variables

x-8=0

We move all terms containing x to the left, all other terms to the right

x=8

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